GCSE · Chemistry · AQA · Spec 8462
Calculating rates of reactions
A reaction fizzes wildly, then calms down, then stops. 'Fast' and 'slow' are fine words, but a chemist wants a number — and a graph hands you one.
Drag along the curve. Watch the red line tip over.
The red line is the tangent. It touches the curve at your point and runs at exactly the same steepness. Its gradient — how many cm³ the volume would rise per second — is the rate of reaction at that moment.
An example reaction that gives off a gas. Drag the point from 0 s towards 40 s: the tangent tips over and the rate falls. The fixed dot marks 40 s, where the curve goes flat — the rate is zero and the reaction has stopped.
Predict, then check
Back to the gas curve at the top: 21 cm³ after 10 s, and 48 cm³ by 40 s, when it stops.
Which mean rate is bigger — over the first 10 s, or over the whole reaction from 0 to 40 s?
The rate at one moment
Problem
Using the gas curve at the top of the page, calculate the rate of reaction at 30 s.
WHAT YOU'VE LEARNED
A quick recap of today's lesson.
How fast is a reaction going? The answer is in how steep its graph is.
What you need to know
- You can follow a reaction's rate by measuring how much reactant is used up, or how much product is formed, as time goes on.
- Mean rate of reaction = quantity of reactant used ÷ time taken, or quantity of product formed ÷ time taken.
- Quantities are measured as a mass in g or a volume in cm³, so the rate is in g/s or cm³/s.
- Higher: with quantities in moles, the rate is in mol/s.
- On a graph of quantity against time, the slope of a tangent measures the rate at that time.
- Higher: calculate the gradient of a tangent as change in quantity ÷ change in time.
The big picture
The rate of a reaction is how fast a reactant is used up or a product is made. A mean rate is the quantity used or formed divided by the time taken, in g/s or cm³/s (mol/s for moles, at Higher). On a quantity–time graph, the rate at any moment is the gradient of the tangent there: steep means fast, flat means stopped.
Key points
Worked example
Problem
Gas is collected from a reaction. After 10 s there are 16 cm³ of gas; after 30 s there are 46 cm³. Calculate the mean rate of reaction between 10 s and 30 s.
⚠ Watch out
Dividing the quantity at one point by its time and calling it the rate at that moment. That gives the mean rate from the start. The rate at a moment is the gradient of the tangent at that time.
Memory hook
Height = how much. Steepness = how fast.
Check yourself
A reactant's mass drops from 8.0 g to 5.0 g in 60 s. Find the mean rate, with units. Why isn't it the rate at 60 s? (0.05 g/s — an average, not a tangent.)
Flashcards
(11)What is the rate of a reaction?
Write the word equation for mean rate of reaction.
You measured a mass in grams, or a volume in cm³. What unit is the rate in?
Higher: what unit is the rate in when the quantity is in moles?
On a quantity–time graph, how do you show the rate at one moment?
What does a steep part of a quantity–time curve tell you?
What does it mean when a quantity–time curve goes flat?
Mean rate vs rate at a moment: what's the difference?
Higher: how do you calculate the gradient of a tangent?
A graph of reactant left slopes downwards. Is the rate negative?
Why use the quantity of reactant USED, not the amount left?
Tap any card to flip it, or use Study as deck to go through them one at a time. In the full lesson these run as a spaced-repetition deck — you rate each card Hard, Good or Easy and the tricky ones keep coming back until they stick.
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