GCSE · Physics · AQA · Spec 8463
Distance–time graphs
Read a graph line and you can tell exactly how fast something moved — no stopwatch needed.
What you need to know
- A straight sloping line on a distance–time graph means constant speed; gradient = speed.
- A horizontal line means the object is stationary — distance is not changing.
- A curve on the graph means the speed is changing — the object is accelerating or decelerating.
- Higher tier: find the speed at a specific instant on a curve by drawing a tangent at that point and calculating its gradient.
The big picture
A distance–time graph shows how far an object has travelled over time. The steeper the line, the faster the object is moving — gradient equals speed. A flat horizontal line means the object is stationary. A curve means the speed is changing (the object is accelerating or decelerating).
TONIGHT'S REVISION
Distance–time graphs
How to read gradient as speed — and spot acceleration from a curve.
Maths & Science · Interpret graphs
Reading a distance–time graph
Use the gradient tools to extract speed from each section of the journey.
Selected tool
Gradient
Reading
Gradient at t = 4s
Value
≈ 12.5 m/s
Steepness of the tangent. On a distance–time graph, gradient = speed at that instant.
Predict, then check
Look at each section description — commit to an answer before you reveal.
A distance–time graph has three sections: (1) a steep straight line, (2) a horizontal flat section, (3) a shallower straight line. Which section shows the object moving at its FASTEST speed?
How to find speed from a distance–time graph
Follow every step in order — this is the method examiners expect to see written down.
Relationship matrix
Tap any cell to reveal it. Tap a column header to read one property down every item.
Each cell hides a short answer and the reason behind it. Predict before you tap.
Process · Closed loop
Higher tier: Finding instantaneous speed from a curve
Use this repeatable cycle whenever the distance–time graph is curved.
Stage 01
Locate the point
AQA Paper 2 — exam technique
AQA mark-scheme practice
Does this student answer contain the phrases that unlock marks?
Question
Describe the motion shown by the distance–time graph. Section A: steep straight line for 10 s. Section B: horizontal line for 5 s. Section C: shallower straight line for 10 s.
Student answer
In section A the object moves at constant speed. In section B the object is stationary. In section C the object moves at constant speed but more slowly than in section A.
Equations you need
Taken directly from the exam-board specification.
v = speed (m/s) · s = distance (m) · t = time (s)
Learn it — you must recall this in the exam
Key points
Worked example
Problem
A cyclist travels 600 m in 40 s at constant speed. What is the cyclist's speed? Show how you would read this from a distance–time graph.
Memory hook
STEEP = SPEEDY, FLAT = FROZEN, CURVE = CHANGING — three words that cover every line shape you will ever see on a distance–time graph.
★ Exam tip
On AQA Paper 2, always show your gradient calculation with a clearly labelled rise-and-run triangle drawn on the graph — examiners award a method mark for the working even if you misread a value. Higher tier: when drawing a tangent to a curve, extend the line as far as possible across the graph before reading off rise and run, to minimise reading errors.
⚠ Watch out
Confusing a steep straight line with acceleration — a steep straight line is FAST CONSTANT SPEED, not speeding up. Only a CURVE means the speed is changing.
Check yourself
Without looking — sketch what a distance–time graph looks like for an object that travels fast, then stops, then travels slowly. What are the three key features of your sketch?
Flashcards
(22)What does the gradient of a distance–time graph equal?
What does a straight sloping line on a distance–time graph show?
What does a horizontal (flat) line on a distance–time graph show?
What does a curve on a distance–time graph show?
Write the equation for speed.
What are the units of speed when distance is in metres and time is in seconds?
A steeper gradient on a distance–time graph means what?
Two objects have straight lines on the same distance–time graph. Object A has a steeper line. What does this mean?
Higher tier: How do you find the speed of an object at a specific instant when the distance–time graph shows a curve?
Higher tier: Why must you draw a tangent to find speed on a curved distance–time graph?
What does a decreasing gradient on a distance–time graph tell you about the object's motion?
An object's distance–time graph shows a horizontal line for 5 s. What is its speed during this time?
How do you calculate the gradient of a straight line on a distance–time graph?
A car travels 300 m in 20 s at constant speed. What is its speed?
What shape is the line on a distance–time graph for a uniformly accelerating object?
Higher tier: On a curved distance–time graph, what does a steeper tangent drawn at a later time indicate?
What two quantities do you need to read from the graph axes to calculate speed?
Higher tier: What is meant by 'instantaneous speed' on a distance–time graph?
An object's distance–time graph shows a curve that gets progressively steeper. What is happening to the object?
Which AQA paper assesses distance–time graphs?
A distance–time graph has gradient = 0. What does this tell you about the object?
If the gradient of a straight section of a distance–time graph is 12, what is the object's speed?
Tap any card to flip it, or use Study as deck to go through them one at a time. In the full lesson these run as a spaced-repetition deck — you rate each card Hard, Good or Easy and the tricky ones keep coming back until they stick.
Learn Distance–time graphs properly — interactive practice, marked questions and flashcards.
Start this lesson freeMore AQA GCSE Physics topics
- Acceleration (a = Δv/t)
- Current, resistance and potential difference (V = I R)
- Density of materials (ρ = m/V)
- Distance and displacement
- Efficiency
- Energy stores and systems
- Gravitational potential energy (Ep = m g h)
- Kinetic energy calculation (Ek = 1/2 m v^2)
- Newton's First Law
- Newton's Second Law (F = m a)
- Power (P = E/t and P = W/t)
- Resultant forces and resolving forces
How this lesson was checked. This AQA GCSE Physics (specification 8463)lesson was published through Lightbulb Learning's human-designed editorial process — the educational standards, accuracy rules and publication checks it must pass were authored and approved by Philip Halpin. It passed subject-specific assessment, automated educational checks and technical publication verification before going live (publication checks completed 2 August 2026). Published pages are monitored, human spot-checking is ongoing across the lesson library, and anything found wrong is corrected or withdrawn. How our lessons are made and checked. Spotted a mistake? Email hello@lightbulblearning.co and we'll review it.