GCSE · Physics · Edexcel · Spec 1PH0
Velocity/time graphs
On a distance–time graph a flat line means stopped. On a velocity–time graph, the same flat line could be a car cruising down a motorway.
A tram's journey from one stop to the next
slide me along the line
Predict, then check
Now switch from the slope of the line to the space underneath it.
From 15 s to 27 s the tram cruises at a steady 15 m/s. How far does it travel in those 12 seconds?
Distance from the area
Problem
How far does the tram travel in the first 15 s of its journey?
WHAT YOU'VE LEARNED
A quick recap of today's lesson.
The slope tells you the acceleration. The space underneath tells you how far.
What you need to know
- A velocity–time graph has velocity on the vertical axis and time on the horizontal axis, so it shows how the velocity changes during the motion.
- The gradient (slope) of a velocity–time graph is the acceleration: acceleration = change in velocity ÷ time taken for that change.
- A steeper line means a bigger acceleration. A horizontal line means constant velocity (zero acceleration). A line sloping downwards means the object is decelerating.
- For a straight sloping section, a = (v − u) ÷ t: read the start velocity u, the end velocity v and the time interval t off the axes. Acceleration is in m/s².
- The distance travelled is the area between the line and the time axis. Split it into rectangles (base × height) and triangles (½ × base × height), using time in s and velocity in m/s, to get metres.
- A horizontal line on a velocity–time graph means moving at constant velocity, not stationary. A stationary object has a line along the time axis (velocity zero).
The big picture
A velocity–time graph shows how an object's velocity changes over time, with velocity up the side and time along the bottom. The gradient of the line is the acceleration: a steeper line means a bigger acceleration, a flat line means constant velocity, and a line sloping down means the object is decelerating. For a straight section, acceleration = change in velocity ÷ time taken, in m/s². The area under the line is the distance travelled: split it into rectangles and triangles, use seconds and m/s, and the answer comes out in metres. A flat line does not mean stopped — a stationary object has a line along the time axis.
Key points
Worked example
Problem
At the end of its journey the tram brakes steadily from 15 m/s at 27 s to a stop at 32 s. Find its acceleration while braking, and how far it travels while braking.
⚠ Watch out
Reading a velocity–time graph as if it were a distance–time graph. A flat line here does not mean the object has stopped — it means it is moving at a constant velocity. Only a line along the time axis (velocity zero) means stationary.
Memory hook
Slope for speeding up, space for how far. The SLOPE of the line tells you the acceleration; the SPACE underneath it tells you the distance.
Check yourself
Cover the page and sketch a velocity–time graph for a bike that speeds up, cruises, then brakes to a stop. Where is the acceleration zero? Shade the distance travelled.
Flashcards
(13)What goes on each axis of a velocity–time graph?
What does the gradient of a velocity–time graph tell you?
Write the equation for acceleration from a change in velocity.
What is the unit of acceleration?
Two sloping sections: one steep, one gentle. Which has the bigger acceleration?
A horizontal line on a velocity–time graph means…?
A line sloping downwards on a velocity–time graph means…?
How does a velocity–time graph show an object that is stationary?
What does the area under a velocity–time line give you?
Why does the area under a velocity–time line equal the distance?
Area of a triangle under the line?
Time in s and velocity in m/s. What unit is the area in?
Reading t for one section of the graph: what do you do?
Tap any card to flip it, or use Study as deck to go through them one at a time. In the full lesson these run as a spaced-repetition deck — you rate each card Hard, Good or Easy and the tricky ones keep coming back until they stick.
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