GCSE · Chemistry · AQA · Spec 8462
Oxidation and reduction in terms of electrons (HT)
When magnesium meets copper sulfate solution, the sulfate does absolutely nothing. The real action is electrons jumping between particles. Follow the electrons and these reactions start making sense.
Chemistry · Redox
Who lost electrons? Who gained them?
Reaction 1: Mg + CuSO₄ → MgSO₄ + Cu. Reaction 2: Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag. Sort each particle by what happens to its electrons.
Still to sort
Oxidised: loses electrons (0)
Its charge goes up, for example a neutral atom becoming a positive ion.
Where the line is: Only electrons count. If it gave electrons away, it was oxidised, whatever it ends up as.
Reduced: gains electrons (0)
Its charge goes down, for example a positive ion becoming a neutral atom.
Where the line is: Look for electrons taken in. In a half equation they sit on the left, with the reactants.
Neither: a spectator ion (0)
Same particle, same charge, before and after.
Where the line is: It is in the beaker and in the full equation, but it neither loses nor gains electrons. Being there is not the same as taking part.
Two displacement reactions and two half equations. Pick a particle (chemists call each one a species), decide what happened to its electrons, then read why.
Watch it done: from full equation to half equations
Problem
Zinc is added to iron(II) sulfate solution: Zn + FeSO₄ → ZnSO₄ + Fe. Write the ionic equation and both half equations, and say which species is oxidised and which is reduced.
WHAT YOU'VE LEARNED
A quick recap of today's lesson.
Whoever loses electrons is oxidised. Whoever gains them is reduced. Whoever does neither is just watching.
What you need to know
- Define oxidation and reduction in terms of electrons.
- Decide which species is oxidised and which is reduced in a reaction, a symbol equation or a half equation, and say why.
- Write the ionic equation for a metal displacement reaction, leaving out the spectator ions.
The big picture
Oxidation is the loss of electrons and reduction is the gain of electrons, and they always happen together. In a displacement reaction the more reactive metal's atoms lose electrons to the less reactive metal's ions. Cross out the spectator ions and you have the ionic equation; split that in two and you have the half equations.
Key points
Worked example
Problem
Aluminium displaces copper from copper sulfate solution. The half equations are Al → Al³⁺ + 3e⁻ and Cu²⁺ + 2e⁻ → Cu. Combine them into the ionic equation and say which species is oxidised and which is reduced.
⚠ Watch out
Calling every ion in the equation oxidised or reduced. Check each one: a spectator ion such as SO₄²⁻ has exactly the same charge before and after, so it gained and lost nothing. It is neither, and it does not belong in the ionic equation.
Memory hook
OIL RIG: Oxidation Is Loss, Reduction Is Gain (of electrons). And picture the spectator ion up in the stands: it's at the match, but it never touches the ball.
Check yourself
Try one on your own: Fe + CuSO₄ → FeSO₄ + Cu. Which species is oxidised, which is reduced, which is the spectator, and what is the ionic equation?
Flashcards
(6)What are oxidation and reduction, in terms of electrons?
What is a spectator ion?
In a metal displacement reaction, what is oxidised and what is reduced?
In a half equation, how can you tell oxidation from reduction?
How do you check a half equation is written correctly?
Why can't oxidation happen without reduction?
Tap any card to flip it, or use Study as deck to go through them one at a time. In the full lesson these run as a spaced-repetition deck — you rate each card Hard, Good or Easy and the tricky ones keep coming back until they stick.
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