GCSE · Chemistry · AQA · Spec 8462
Percentage yield
A reaction can be perfectly planned and still give less product than the calculation predicts.
CHEMISTRY · YIELD
In this model the theoretical maximum is fixed at 20 g. Drag the actual amount and watch the fraction and percentage move together.
From masses to a percentage
Start with actual over theoretical so the comparison cannot accidentally be reversed.
Higher challenge: theoretical mass first
Problem
12 g of magnesium reacts with oxygen: 2Mg + O₂ → 2MgO. The reaction produces 16 g of magnesium oxide. Calculate the percentage yield. Use Ar: Mg = 24, O = 16.
Higher-tier route: calculating the theoretical product mass from a reactant mass and a balanced equation is Higher-only content.
See where the theoretical ratio comes from
Read the coefficients as mole ratios, not as masses.
Tap a molecule to see what it does in the reaction.
Higher-tier route: use a balanced equation to calculate the theoretical mass before finding percentage yield.
CHEMISTRY · QUANTITATIVE
Percentage yield
Compare what you actually make with the maximum amount the reaction could theoretically make.
What you need to know
- Yield is the amount of product actually obtained from a reaction.
- Percentage yield compares actual product with the maximum theoretical amount: (actual ÷ theoretical) × 100.
- Percentage yield may be below 100% because a reaction may be reversible, product may be lost during separation, or reactants may react in unexpected ways.
- Higher-only: a balanced equation can be used with a reactant mass to calculate the theoretical mass of product.
The big picture
Percentage yield compares the amount of product actually obtained with the maximum theoretical amount. It is calculated as (actual ÷ theoretical) × 100. A yield can be below 100% because a reversible reaction may not go to completion, product can be lost during separation, or reactants can form unexpected products. For higher calculations, use the balanced equation to find the theoretical product mass first.
Key points
Worked example
Problem
A reaction has a theoretical product mass of 50 g and produces 35 g. Calculate the percentage yield.
Memory hook
A-T-100: Actual over Theoretical, then ×100.
★ Exam tip
Write actual ÷ theoretical before entering numbers. If a theoretical mass must be calculated first, keep that working separate and clearly labelled.
⚠ Watch out
Dividing theoretical by actual. That reverses the comparison and can give a percentage above 100 for an ordinary yield question.
Check yourself
A reaction should make 40 g but produces 30 g. What is its percentage yield, and name one reason it could be below 100%?
Flashcards
(20)What is the yield of a reaction?
What is theoretical yield?
What does percentage yield compare?
What is the percentage-yield formula?
Which quantity goes in the numerator of the percentage-yield calculation?
Which quantity goes in the denominator?
What does a 100% yield mean?
What does an 80% yield mean?
Why can a reversible reaction reduce yield?
How can separation reduce yield?
How can unexpected reactions reduce yield?
Theoretical mass = 25 g and actual mass = 20 g. Percentage yield?
Theoretical mass = 60 g and actual mass = 45 g. Percentage yield?
Actual mass = 18 g and percentage yield = 90%. What theoretical mass would match this?
Why should actual and theoretical amounts use compatible units?
Does a low percentage yield automatically tell you which loss mechanism occurred?
Higher: what does a balanced equation provide for a theoretical-mass calculation?
Higher: after finding moles of product, how do you find theoretical mass?
Higher: in 2Mg + O₂ → 2MgO, what is the mole ratio Mg:MgO?
Higher: 12 g Mg is 0.50 mol. How many moles of MgO are theoretically formed?
Tap any card to flip it, or use Study as deck to go through them one at a time. In the full lesson these run as a spaced-repetition deck — you rate each card Hard, Good or Easy and the tricky ones keep coming back until they stick.
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Keep me postedMore AQA GCSE Chemistry topics
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- Conservation of mass and balanced equations
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